pyspark.pandas.DataFrame.apply¶
-
DataFrame.
apply
(func: Callable, axis: Union[int, str] = 0, args: Sequence[Any] = (), **kwds: Any) → Union[Series, DataFrame, Index][source]¶ Apply a function along an axis of the DataFrame.
Objects passed to the function are Series objects whose index is either the DataFrame’s index (
axis=0
) or the DataFrame’s columns (axis=1
).See also Transform and apply a function.
Note
when axis is 0 or ‘index’, the func is unable to access to the whole input series. pandas-on-Spark internally splits the input series into multiple batches and calls func with each batch multiple times. Therefore, operations such as global aggregations are impossible. See the example below.
>>> # This case does not return the length of whole series but of the batch internally ... # used. ... def length(s) -> int: ... return len(s) ... >>> df = ps.DataFrame({'A': range(1000)}) >>> df.apply(length, axis=0) 0 83 1 83 2 83 ... 10 83 11 83 dtype: int32
Note
this API executes the function once to infer the type which is potentially expensive, for instance, when the dataset is created after aggregations or sorting.
To avoid this, specify the return type as Series or scalar value in
func
, for instance, as below:>>> def square(s) -> ps.Series[np.int32]: ... return s ** 2
pandas-on-Spark uses return type hints and does not try to infer the type.
In case when axis is 1, it requires to specify DataFrame or scalar value with type hints as below:
>>> def plus_one(x) -> ps.DataFrame[int, [float, float]]: ... return x + 1
If the return type is specified as DataFrame, the output column names become c0, c1, c2 … cn. These names are positionally mapped to the returned DataFrame in
func
.To specify the column names, you can assign them in a pandas style as below:
>>> def plus_one(x) -> ps.DataFrame[("index", int), [("a", float), ("b", float)]]: ... return x + 1
>>> pdf = pd.DataFrame({'a': [1, 2, 3], 'b': [3, 4, 5]}) >>> def plus_one(x) -> ps.DataFrame[ ... (pdf.index.name, pdf.index.dtype), zip(pdf.dtypes, pdf.columns)]: ... return x + 1
- Parameters
- funcfunction
Function to apply to each column or row.
- axis{0 or ‘index’, 1 or ‘columns’}, default 0
Axis along which the function is applied:
0 or ‘index’: apply function to each column.
1 or ‘columns’: apply function to each row.
- argstuple
Positional arguments to pass to func in addition to the array/series.
- **kwds
Additional keyword arguments to pass as keywords arguments to func.
- Returns
- Series or DataFrame
Result of applying
func
along the given axis of the DataFrame.
See also
DataFrame.applymap
For elementwise operations.
DataFrame.aggregate
Only perform aggregating type operations.
DataFrame.transform
Only perform transforming type operations.
Series.apply
The equivalent function for Series.
Examples
>>> df = ps.DataFrame([[4, 9]] * 3, columns=['A', 'B']) >>> df A B 0 4 9 1 4 9 2 4 9
Using a numpy universal function (in this case the same as
np.sqrt(df)
):>>> def sqrt(x) -> ps.Series[float]: ... return np.sqrt(x) ... >>> df.apply(sqrt, axis=0) A B 0 2.0 3.0 1 2.0 3.0 2 2.0 3.0
You can omit type hints and let pandas-on-Spark infer its type.
>>> df.apply(np.sqrt, axis=0) A B 0 2.0 3.0 1 2.0 3.0 2 2.0 3.0
When axis is 1 or ‘columns’, it applies the function for each row.
>>> def summation(x) -> np.int64: ... return np.sum(x) ... >>> df.apply(summation, axis=1) 0 13 1 13 2 13 dtype: int64
You can omit type hints and let pandas-on-Spark infer its type.
>>> df.apply(np.sum, axis=1) 0 13 1 13 2 13 dtype: int64
>>> df.apply(max, axis=1) 0 9 1 9 2 9 dtype: int64
Returning a list-like will result in a Series
>>> df.apply(lambda x: [1, 2], axis=1) 0 [1, 2] 1 [1, 2] 2 [1, 2] dtype: object
To specify the types when axis is ‘1’, it should use DataFrame[…] annotation. In this case, the column names are automatically generated.
>>> def identify(x) -> ps.DataFrame[('index', int), [('A', np.int64), ('B', np.int64)]]: ... return x ... >>> df.apply(identify, axis=1) A B index 0 4 9 1 4 9 2 4 9
You can also specify extra arguments.
>>> def plus_two(a, b, c) -> ps.DataFrame[np.int64, [np.int64, np.int64]]: ... return a + b + c ... >>> df.apply(plus_two, axis=1, args=(1,), c=3) c0 c1 0 8 13 1 8 13 2 8 13